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Asked by pattianne - 4 years ago
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thinkfirst Level 18 / Scientist
Answered 3 years ago
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In neutral water: concentration of H3O+ = concentration of OH- = 10^-7

2H2O <-> OH- + H3O+

The addition of H+ will drive this equilibrium reaction to the left and remove OH-

You should look at the power numbers to calculate the answer. They will always add up to -14:

OH- + H3O+ = -14
OH- + -6 = -14
OH- = -8

i.e. when [H3O+] = -6, [OH-] = -8

http://en.wikipedia.org/wiki/Self-ioniza...
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