CaC2 + 2H2O >> C2H2 + Ca(OH)2
32 / 64.1 g/mol =0.499 moles of CaC2
Moles H2O = 2 x 0.499 = 0.998
Mass water = 0.998 mol x 18.02 g/mol = 18.0 g
Moles C2H2 produced = 0.499
Mass C2H2 = 0.499 mol x 26.038 g/mol =13.0 g
I'm homeschooled and I dont understand the following problems. :[ I studied and did all the work, but i just need the answers to these. It's my final semester of chem and i just wanna get it done and graduate! please help :[ i cant graduate if i fail
1. Acetylene gas (C2H2) is produced from calcium carbide (CaC2) and water. Calcium hydroxide is the other product. If 32 grams of calcium carbide are consumed, how many grams of water are needed?
2. In the reaction above ^^, how many grams of acetylene gas is produced?
3. Oxygen gas is united with hydrogen gas to form water vapor. How many grams of oxygen are necessary to produce 32.0 grams of water?
2 years ago
Best Answer - Chosen by Voters
CaC2 + 2 H2O = C2H2 + Ca(OH)2
moles CaC2 = 32 g /64 g/mol= 0.50
moles water required = 0.50 x 2 = 1.0
mass water = 1.0 mol x 18 g/mol= 18 g
moles C2H2 produced = 0.50
mass C2H2 = 0.50 x 26 g/mol= 13 g
2 H2 + O2 = 2 H2O
moles water = 32 / 18 =1.78
moles O2 = 1.78/2=0.89
mass O2 = 0.89 x 32 g/mol=28.5 g
I could do it myself but it’s not my homework so I copied it. But it is right