Asked by
Emack
 7 years ago


Best Answer

The given data are.
m = 150g = 0.15kg
change in temperature = 20 c
the specific heat of water = 4.187 KJ / Kg k
we know that the quantity of heat required
= mass x spe.heat x change in temp.
= 0.15 x 4.187 x 20
= 12.561 KJ.

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The given data are.
m = 150g = 0.15kg
change in temperature = 20 c
the specific heat of water = 4.187 KJ / Kg k
we know that the quantity of heat required
= mass x spe.heat x change in temp.
= 0.15 x 4.187 x 20
= 12.561 KJ.

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